225=225-16t^2

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Solution for 225=225-16t^2 equation: 



225=225-16t^2

We move all terms to the left:

225-(225-16t^2)=0

We get rid of parentheses

16t^2-225+225=0

We add all the numbers together, and all the variables

16t^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{32}=0$

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